24x^2+8x-80=0

Solution for 24x^2+8x-80=0 equation:

24x^2+8x-80=0

a = 24; b = 8; c = -80;
Δ = b2-4ac
Δ = 82-4·24·(-80)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*24}=\frac{-96}{48}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*24}=\frac{80}{48}
=1+2/3
$